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<title>Problem 1701. -- [Usaco2007 Jan]Cow School牛学校 -- 衡阳八中OJ离线版-2012-02-29</title><center><h2>1701: [Usaco2007 Jan]Cow School牛学校</h2><span class=green>Time Limit: </span>5 Sec&nbsp;&nbsp;<span class=green>Memory Limit: </span>64 MB<br><span class=green>Submit: </span>78&nbsp;&nbsp;<span class=green>Solved: </span>19<br>[<a href='submitpage.php?id=1701'>Submit</a>][<a href='problemstatus.php?id=1701'>Status</a>][<a href='bbs.php?id=1701'>Discuss</a>]</center><h2>Description</h2><div class=content>Bessy 正在上学并且分数还不错. 她考了N (一个数据中1 <= N <= 50,000, 其
余数据 1 <= N <= 50,00) 次试,每次考试得分为T_i, 满分为P_i(0 <= T_i <=
P_i < 40,000; 0 < P_i).

在计算总分时,她的老师先将把分数(P_i/T_i)最高的D个试卷去掉,然后将其余P_i
的和除以其余T_i的和作为Bessy的分数. Bessy精通数学,所以很快发觉这并没
有想象中那么好.

Bessy想告诉她的老师所有附和以下条件的D: 如果令一组(D个)分数去掉,她的分
数回比老师算出来的更高.

Bessy 很惊讶地发现她没有两次考试得分百分点是一样的.

</div><h2>Input</h2><div class=content>*第一行: N

*第2..N+1行: 第i行里有 T_i 和 P_i.

</div><h2>Output</h2><div class=content>* 第一行: K, 符合条件的D的个数.

*第2..K+1行: 按递增顺序,每行一个符合条件的D.

</div><h2>Sample Input</h2>
			<div class=content><span class=sampledata>5<br />
1 2<br />
5 9<br />
3 8<br />
4 10<br />
1 3<br />
<br />
输入解释:<br />
<br />
Bessy 考了5门试, 分数分别为1/2, 5/9, 3/8, 4/10, 1/3.<br />
</span></div><h2>Sample Output</h2>
			<div class=content><span class=sampledata>2<br />
1<br />
2<br />
<br />
输出解释:<br />
<br />
当D=1时, 去掉1/3将使总分变成13/29, 而去掉3/8则得到11/24.<br />
<br />
当D=2时, 去掉1/3和3/8得到总分10/21. 更高的7/14则能由去掉3/8和4/10<br />
得到.<br />
</span></div><h2>HINT</h2>
			<div class=content><p></p></div><h2>Source</h2>
			<div class=content><p><a href='problemset.html?search=Gold'>Gold</a></p></div><center>[<a href='submitpage.php?id=1701'>Submit</a>][<a href='problemstatus.php?id=1701'>Status</a>][<a href='bbs.php?id=1701'>Discuss</a>]</center>﻿<br>

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